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> 設a1=22-02,a2=32-12,…,an=(n+1)2-(n-1)2(n爲大於1的整數)(1)計算a15...

設a1=22-02,a2=32-12,…,an=(n+1)2-(n-1)2(n爲大於1的整數)(1)計算a15...

問題詳情:

a1=22-02,a2=32-12,…,an=(n+1)2-(n-1)2(n爲大於1的整數)

(1)計算a15的值;

(2)透過拼圖你發現前三個圖形的面積之和與第四個正方形的面積之間有什麼關係:

__________________________________(用含ab的式子表示);


設a1=22-02,a2=32-12,…,an=(n+1)2-(n-1)2(n爲大於1的整數)(1)計算a15...
設a1=22-02,a2=32-12,…,an=(n+1)2-(n-1)2(n爲大於1的整數)(1)計算a15... 第2張
設a1=22-02,a2=32-12,…,an=(n+1)2-(n-1)2(n爲大於1的整數)(1)計算a15... 第3張
設a1=22-02,a2=32-12,…,an=(n+1)2-(n-1)2(n爲大於1的整數)(1)計算a15... 第4張
 

①              ②              ③              ④                                                    

設a1=22-02,a2=32-12,…,an=(n+1)2-(n-1)2(n爲大於1的整數)(1)計算a15... 第5張(3)根據(2)中結論,探究an=(n+1)2-(n-1)2是否爲4的倍數.

【回答】

(1)a15=162-142=256-196=60·······································································(2分)

(2) (a+b)2=a2+2ab+b2  ··············································································(4分)

(3) an=(n+1)2-(n-1)2 =(n2+2n+1)-(n2-2n+1) =n2+2n+1-n2+2n-1=4n

w    W w  .X k b 1.c O m

     設a1=22-02,a2=32-12,…,an=(n+1)2-(n-1)2(n爲大於1的整數)(1)計算a15... 第6張是4的倍數.  ···············································································(6分)

知識點:有理數的乘方

題型:解答題

標籤: a232 整數 ann12 A15 a122
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