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> x2﹣4x+1=0(*法)                                         ...

x2﹣4x+1=0(*法)                                         ...

問題詳情:

x2﹣4x+1=0(*法)                                                                       

【回答】

x2﹣4x+4=4﹣1,                                                                                

∴(x﹣2)2=3,                                                                                

∴x=2±x2﹣4x+1=0(*法)                                         ...x2﹣4x+1=0(*法)                                         ... 第2張;                                                                                     

知識點:解一元二次方程

題型:計算

標籤: x2 4x10
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