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> 如图所示,杠杆处于平衡状态,如果将物体A和B同时向靠近支点的方向移动相同的距离,下列判断正确的是(  ) A....

如图所示,杠杆处于平衡状态,如果将物体A和B同时向靠近支点的方向移动相同的距离,下列判断正确的是(  ) A....

问题详情:

如图所示,杠杆处于平衡状态,如果将物体A和B同时向靠近支点的方向移动相同的距离,下列判断正确的是(  )

A. 杠杆仍能平衡 B. 杠杆不能平衡,左端下沉

C. 杠杆不能平衡,右端下沉 D. 无法判断


如图所示,杠杆处于平衡状态,如果将物体A和B同时向靠近支点的方向移动相同的距离,下列判断正确的是(  ) A....


【回答】

 原来杠杆在水平位置处于平衡状态,此时作用在杠杆上的力分别为物体A、B的重力,其对应的力臂分别为OC、OD,

根据杠杆的平衡条件可得:mAgOC=mBgOD,由图示可知,OC<OD.所以mA>mB,

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当向支点移动相同的距离△L时,两边的力臂都减小△L,此时左边的力矩为:mAg(OC﹣△L)=mAgOC﹣mAg△L,

右边的力矩为:mBg(OD﹣△L)=mBgOD﹣mBg△L,由于mA>mB,所以mAg△L>mBg△L;

所以:mAgOC﹣mAg△L<mBgOD﹣mBg△L.

因此杠杆将向悬挂B物体的一端即右端倾斜.

故选C.

知识点:杠杆

题型:选择题

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