- 問題詳情:如圖,在矩形ABCD中,AB=3,BC=4.M、N在對角線AC上,且AM=CN,E、F分別是AD、BC的中點.(1)求*:△ABM≌△CDN;(2)點G是對角線AC上的點,∠EGF=90°,求AG的長.【回答】(1)*∵四邊形ABCD是矩形,∴AB∥CD,∴∠MAB=∠NCD.在△ABM和△CDN中,∴△ABM≌△CDN;(2)解:如圖,連接EF,交AC於點O.在△AEO和△CFO中,∴...
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- Two-waypowersupplyletsyouuseeitherbatteriesorACadaptor(soldseparately).ConsumablessuchasACadaptorarecoveredforupto3monthsfromthedateofpurchase....
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- HXN5High-powerACDriveDieselLocomotiveCarbodyofNXN3high-powerACdiesellocomtoveThepaperintroducesanovelmicrocomputer-basedwithnon-contacttechnicalityofthehighpowerACcompensatedstabilizer....
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- 問題詳情:已知點B在直線AC上,AB=8cm,AC=18cm,p、Q分別是AB、AC的中點,則PQ=____.【回答】5cm或9cm.知識點:直*、*線、線段題型:填空題...
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- FouriertransformACvoltammetrysiliconcontrolledvoltagestabilizedAClightadjusterAC,DCorAirmotorpoweroptions.ResearchonSinglePhaseAC/ACOnvertersBasedonSimpleTopologies;ThevariablefrequencyACcontrollermountsdirectlyontheACmotor.TheACoutletishousedinrobus...
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- 1、AutomaticexchangeforDCandACsupply.2、DisconnecttheACsupplyleadplugfromtheACoutletwhentheunitinnotituseforextendedperiods.3、RemovetheACsupplyleadbeforeservicingorcleaningheads,rolleretc.4、InsertingtheACsupplyleadintotheunitautomaticallydisconnect...
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- UsingACcontactorformotor’sphasebreakprotectionisimproperInsideisinstalledACcontactor,thermalreplay,self-settableconversionswitch.FuzzyComprehensiveEvaluationandControlofBestClosingMakingAngleofRotationalACcontactorTheutilitymodelbelongstoasilencinga...
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- 問題詳情:已知:AB=AC,且AB⊥AC,D在BC上,求*:.【回答】*見解析【分析】作AE⊥BC於E,由於∠BAC=90°,AB=AC,得到△BAC是等腰直角三角形,再由等腰直角三角形的*質得到BE=AE=EC,進而得到BD=AE-DE,DC=AE+DE,代入BD2+CD2計算,結合勾股定理,即可得到結論.【詳解】作AE⊥BC於E,如圖所示.∵AB=AC,且AB⊥...
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- 1、AC/DCandDC/ACConvertyCircuitsinPowerSupplyEquipment;2、StudyonDoubly-fedInductionGenerationSystemwithAC/DC/ACExcitationConverter;3、ElectroMagneticCompatibilityDesignofAC/DC/ACConverterUsedinWindPowerGenerator;4、ResearchontheDC/ACInverterSupplies...
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- 問題詳情:如圖,在△ABC中,AC=BC,∠ACB=90°,AE平分∠BAC交BC於E,BD⊥AE於D,DF⊥AC交AC的延長線於F,連接CD,給出四個結論:①∠ADC=45°;②BD=AE;③AC+CE=AB;④AB﹣BC=2FC;其中正確的結論有( )A.1個 B.2個 C.3個 D.4個【回答】D【考點】全等三角形的判定與*質;角平分線的*質;等腰直角...
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- 問題詳情:如圖,在▱ABCD中,AC是對角線,BE⊥AC,DF⊥AC,垂足分別為點E,F,求*:AE=CF.【回答】【解答】*:如圖, ∵四邊形ABCD是平行四邊形,∴AB=CD,AB∥CD,∴∠BAE=∠DCF.又BE⊥AC,DF⊥AC,∴∠AEB=∠CFD=90°.在△ABE與△CDF中,,∴得△ABE≌△CDF(AAS),∴AE=CF.知識點:各地中考題型:解答題...
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- 問題詳情:如圖,在△ABC中,AB=AC,∠A=36°,BD平分∠ABC交AC於點D,若AC=2,則AD的長是( )A. B. C.-1 D.+1【回答】C知識點:相似三角形題型:選擇題...
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- 問題詳情:如圖,AD⊥AE,AB⊥AC,AD=AE,AB=AC.求*:△ABD≌△ACE. 【回答】*:∵AD⊥AE,AB⊥AC,∴∠CAB=∠DAE=90°.∴∠CAB+∠CAD=∠DAE+∠CAD,即∠BAD=∠CAE.在△ABD和△ACE中,∴△ABD≌△ACE.知...
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- 問題詳情:題面:如圖,已知AC⊥BC,BD⊥AD,AC與BD交於O,AC=BD.求*:(1)BC=AD; (2)△OAB是等腰三角形.【回答】詳解:(1)∵AC⊥BC,BD⊥AD,∴△ABC與△BAD是直角三角形,在△ABC和△BAD中,∵AC=BD,AB=BA,∠ACB=∠BDA=90°,∴△ABC≌△BAD(HL).∴BC=AD.(2)∵△ABC≌△BAD,∴∠CAB=∠DBA,∴OA=...
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- 問題詳情:OneOctobermorning,Igotofftheall-nighttraininMandalay,acityinMyanmar.Aroughmancameupandofferedtoshowmearound.ThepriceheaskedwaslessthanIwouldpayforabarofchocolateathome.SoIclimbedintohistrishaw(三輪車).Ashewasshowingmearound,hetoldmehowhehadco...
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- 問題詳情:如圖,在△ABC中,AB=AC,AC的垂直平分線分別交BC、AC於點D、E. (1)若AC=12,BC=15,求△ABD的周長;(2)若∠B=20°,求∠BAD的度數. 【回答】知識點:畫軸對稱圖形題型:解答題...
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- 問題詳情:如圖,AB=AC,AB⊥AC,AD⊥AE,且∠ABD=∠ACE.求*:BD=CE.【回答】*:∵AB⊥AC,AD⊥AE,∴∠BAE+∠CAE=90°,∠BAE+∠BAD=90°,∴∠CAE=∠BAD.又AB=AC,∠ABD=∠ACE,∴△ABD≌△ACE(ASA).∴BD=CE.知識點:各地中考題型:解答題...
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- 問題詳情:如圖,∠A=∠E,AC⊥BE,AB=EF,BE=10,CF=4,則AC=.【回答】6.【考點】全等三角形的判定與*質.【分析】由AAS*△ABC≌△EFC,得出對應邊相等AC=EC,BC=CF=4,求出EC,即可得出AC的長.【解答】解:∵AC⊥BE,∴∠ACB=∠ECF=90°,在△ABC和△EFC中,,∴△ABC≌△EFC(AAS),∴AC=EC,BC=CF=4,∵EC=BE﹣BC=10﹣4...
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- 問題詳情:DoyouknowwhatschoollifeislikeinSingapore?InSingapore,aclassonlylastshalfanhour,buttherearenobreaksbetweenclasses.Thestudentsonlyhavea30-minuteteabreakafter3or4classes.Theydonotdoeyeexercises.YaoSuyusaidoureyeexerciseswereunfamiliar(不熟悉)toh...
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- 問題詳情:已知:如圖,四邊形ABCD的對角線AC,BD交於點O,BE⊥AC於E,DF⊥AC於F,點O既是AC的中點,又是EF的中點.(1)求*:△BOE≌△DOF.(2)若OA=BD,則四邊形ABCD是什麼特殊四邊形?説明理由.【回答】【解析】(1)∵BE⊥AC,DF⊥AC,∴∠BEO=∠DFO=90°.又∵∠EOB=∠FOD,OE=OF,∴△BOE...
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- 問題詳情:TheaverageFacebookuserintheUnitedStateshas245friends,accordingtoastudy________inFebruary.A.publishing B.publishedC.publish D.topublish【回答】B知識點:非謂語動詞題型:選擇題...
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- 問題詳情:MoreAmericanpeopletaketheirtroubleswiththemonholiday,accordingtoanewsurvey.Although40percentsaidthatthemainreasonforgoingawayistoescapepressure(壓力)fromwork,almostallsaidtheyworrymorethantheydoathome.Onlyfourinevery100saidthattheyarehappyand...
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- 問題詳情:已知:如圖,DE⊥AC,BF⊥AC,AD=BC,DE=BF,.求*:AB∥DC【回答】.∵DE⊥AC,BF⊥AC,∴∠AED=∠CFB=90°∠AFB=∠CED=90°…………1分在Rt△ADE和Rt△BCF中∴Rt△ADE≌Rt△BCF(HL)…………3分∴AE=CF…………4分∴AE+EF=CF+EF 即AF=CE…………5分在△AFB和△CED中…………7分...
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- 問題詳情:如圖,D、E分別是AB、AC的中點,CD⊥AB於D,BE⊥AC於E,求*:AC=AB.【回答】【考點】軸對稱的*質;全等三角形的判定.【專題】*題.【分析】作輔助線:連接BC,由CD垂直於AB,且D為AB中點,即CD所在直線為AB的垂直平分線,根據線段垂直平分線上的點到線段兩端點的距離相等,得到AC=BC,又E為AC...
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- 1、90-wattACadapterandpowercord2、"RechangethebatteryorplugtheACadapteroutputintotheACadapter3、PlugtheACadapterinandprintagain.4、ThebalanceispoweredbyanACadapter.5、PlugintheACadapterandrestartyournotebook.6、Whenusingthepowercable,insertthepowerc...
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