當前位置:中文谷 >

關於S.的百科

如圖,由a、b、c三個粗細不同的部分連線而成的圓筒固定在水平面上,截面積分別為2S、S和S.已知大氣壓強為p0...
物體在水平恆力F的作用下,在光滑的水平面上由靜止前進了路程S.再進入一個粗糙水平面.又繼續前進了路程S.設F在...
討論力F在下列幾種情況下做功的多少(  )(1)用水平推力F推質量是m的物體在光滑水平面上前進了s.(2)用水...
Fe2O3(s)+C(s)===CO2(g)+2Fe(s)  ΔH=+234.1kJ/molC(s)+O2(g...
  • Fe2O3(s)+C(s)===CO2(g)+2Fe(s)  ΔH=+234.1kJ/molC(s)+O2(g...

  • 問題詳情:Fe2O3(s)+C(s)===CO2(g)+2Fe(s)  ΔH=+234.1kJ/molC(s)+O2(g)===CO2(g)ΔH=-393.5kJ/mol則2Fe(s)+O2(g)===Fe2O3(s)的ΔH等於()A.-824.4kJ/mol             B.-627.6kJ/molC.-744.7kJ/mol             D.-169.4kJ/mol【回答】【*】A【解析】設題給兩...
  • 23826
EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturali...
  • EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturali...

  • 問題詳情:EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturalist.InTheFutureofLife,hetakesusonatouroftheworld'snaturalresources.Howaretheyused?Whathasbeenlost?Whatremainsandisitabletocontinuewiththepresentspeedofuse?Wilsonalsopointsouttheneedtoun...
  • 9963
已知反應①:CO(g)+CuO(s)CO2(g)+Cu(s)和反應②:H2(g)+CuO(s)Cu(s)+H2...
  • 已知反應①:CO(g)+CuO(s)CO2(g)+Cu(s)和反應②:H2(g)+CuO(s)Cu(s)+H2...

  • 問題詳情:已知反應①:CO(g)+CuO(s)CO2(g)+Cu(s)和反應②:H2(g)+CuO(s)Cu(s)+H2O(g)在相同的某溫度下的平衡常數分別為K1和K2,該溫度下反應③:CO(g)+H2O(g)CO2(g)+H2(g)的平衡常數為K。則下列說法正確的是A.反應①的平衡常數K1=B.反應③的平衡常數K=C.對於反應③,恆容時,溫度升高,H2濃度減小,...
  • 14115
 已知:2NH4Cl(s)+Ca(OH)2(s)     CaCl2(s) +2NH3↑+2H2O,現將107...
  •  已知:2NH4Cl(s)+Ca(OH)2(s)     CaCl2(s) +2NH3↑+2H2O,現將107...

  • 問題詳情: 已知:2NH4Cl(s)+Ca(OH)2(s)     CaCl2(s) +2NH3↑+2H2O,現將107gNH4Cl晶體和111g熟石灰混合後,充分加熱使之完全反應。求:  (1)產生的氨氣在標準狀況時的體積為多少?  (2)將所得氨氣全部溶於200mL水中,若所得氨水的密度為0.936g·cm-3,則該氨水的物質的量濃度為多少...
  • 9798
EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturali...
  • EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturali...

  • 問題詳情:EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturalist.InTheFutureofLife,hetakesusonatouroftheworld'snaturalresources.Howaretheyused?Whathasbeenlost?Whatremainsandisitabletocontinuewiththepresentspeedofuse?Wilsonalsopointsouttheneedtoun...
  • 9953
 水的三態的熵值的大小關係正確的是(    )A.S(s)>S(l)>S(g)      B.S(l)>S(s...
5℃、101kPa下:①2Na(s)+1/2O2(g)=Na2O(s)△H1=-414k/mol②2Na(s)...
  • 5℃、101kPa下:①2Na(s)+1/2O2(g)=Na2O(s)△H1=-414k/mol②2Na(s)...

  • 問題詳情:5℃、101kPa下:①2Na(s)+1/2O2(g)=Na2O(s)△H1=-414k/mol②2Na(s)+O2(g)=Na2O2(s)△H2=-511kJ/mol下列說法正確的是   (   )   A.①和②生成等物質的量的產物,轉移的電子數相同   B.Na與足量O2反應生成Na2O,隨溫度升高生成Na2O的速率逐漸加快  C.  D.①和②產物中的*陽...
  • 6357
EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturali...
  • EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturali...

  • 問題詳情:EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturalist.InTheFutureofLife,hetakesusonatouroftheworld'snaturalresources.Howaretheyused?Whathasbeenlost?Whatremainsandisitabletocontinuewiththepresentspeedofuse?Wilsonalsopointsouttheneedtoun...
  • 9953
已知:Fe2O3(s)+C(s)==CO2(g)+2Fe(s)  ΔH1=+234.1kJ·mol-1,C(s...
  • 已知:Fe2O3(s)+C(s)==CO2(g)+2Fe(s)  ΔH1=+234.1kJ·mol-1,C(s...

  • 問題詳情:已知:Fe2O3(s)+C(s)==CO2(g)+2Fe(s)  ΔH1=+234.1kJ·mol-1,C(s)+O2(g)==CO2(g)   ΔΗ2=-393.5kJ·mol-1,則2Fe(s)+O2(g)==Fe2O3(s)的ΔH是()A.-824.4kJ·mol-1B.-627.6kJ·mol-1C.-744.7kJ·mol-1D.-169.4kJ·mol-1【回答】A知識點:化學的反應中的物...
  • 22648
在25℃101kPa下,①2Na(s)+O2(g)═Na2O(s)△H1=﹣414kJ/mol, ②2Na(s...
  • 在25℃101kPa下,①2Na(s)+O2(g)═Na2O(s)△H1=﹣414kJ/mol, ②2Na(s...

  • 問題詳情:在25℃101kPa下,①2Na(s)+O2(g)═Na2O(s)△H1=﹣414kJ/mol, ②2Na(s)+O2(g)═Na2O2(s)△H2=﹣511kJ/mol,下列說法正確的是()A.①和②產物的*陽離子個數比不相等B.①和②生成等物質的量的產物,轉移電子數不同C.常溫下Na與足量O2反應生成Na2O,隨溫度升高生成Na2O的速率逐漸加快D.25℃101kPa下...
  • 25204
EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturali...
  • EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturali...

  • 問題詳情:EdwardWilsonisAmerica's,ifnottheworld's,leadingnaturalist.InTheFutureofLife,hetakesusonatouroftheworld'snaturalresources.Howaretheyused?Whathasbeenlost?Whatremainsandisitabletocontinuewiththepresentspeedofuse?Wilsonalsopointsouttheneedtoun...
  • 9963
已知:①Zn(s)+O2(g)=ZnO(s)ΔH=-348.3kJ·mol-1       ②2Ag(s)+O...
  • 已知:①Zn(s)+O2(g)=ZnO(s)ΔH=-348.3kJ·mol-1       ②2Ag(s)+O...

  • 問題詳情:已知:①Zn(s)+O2(g)=ZnO(s)ΔH=-348.3kJ·mol-1       ②2Ag(s)+O2(g)=Ag2O(s)ΔH=-31.0kJ·mol-1   則Zn與Ag2O反應生成ZnO和Ag的熱化學方程式為A.2Zn(s)+2Ag2O(s)===2ZnO(s)+4Ag(s)ΔH=-634.6kJ·mol-1B.Zn+Ag2O===ZnO+2AgΔH=+317.3kJ·mol-1C.Zn(s)+Ag2O(s)===ZnO(s)+2Ag(...
  • 13828
已知:Fe2O3(s)+3/2C(s)=3/2CO2(g)+2Fe(s)△H=234.1kJ⋅mol−1C(s...
  • 已知:Fe2O3(s)+3/2C(s)=3/2CO2(g)+2Fe(s)△H=234.1kJ⋅mol−1C(s...

  • 問題詳情:已知:Fe2O3(s)+3/2C(s)=3/2CO2(g)+2Fe(s)△H=234.1kJ⋅mol−1C(s)+O2(g)=CO2(g)△H=−393.5kJ⋅mol−1則2Fe(s)+3/2O2(g )=Fe2O3(s) 的△H是( )A. −824.4kJ⋅mol−1           B. −627.6kJ⋅mol−1C. −744.7kJ⋅mol−1           ...
  • 8720
i是虛數單位,若*S={-1,0,1},則(  )(A)i∈S   (B)i2∈S  (C)i3∈S   (...
已知①CaCO3(s)==CaO(s)+CO2(g)僅在高溫下自發;②2KClO3(s)==2KCl(s)+3...
  • 已知①CaCO3(s)==CaO(s)+CO2(g)僅在高溫下自發;②2KClO3(s)==2KCl(s)+3...

  • 問題詳情:已知①CaCO3(s)==CaO(s)+CO2(g)僅在高溫下自發;②2KClO3(s)==2KCl(s)+3O2(g)在任何溫度下都自發,下面有幾組焓變資料,其中可能正確的是(    )。A.△H1=-178.32kJ·mol-1△H2=-78.3kJ·mol-1B.△H1=178.32kJ·mol-1△H2=-78.3kJ·mol-1C.△H1=-178.32kJ·mol-1 △H2=78.3kJ·mol-1D....
  • 6120
黑火*是*古代的四大發明之一,其*的熱化學方程式為:S(s)+2KNO3(s)+3C(s)==K2S(s)...
已知S(s)===S(g) ΔH1,S(g)+O2(g)===SO2(g) ΔH2,則S(s)燃燒的熱化學方程...
是虛數單位,若*,則(  )A.∈S     B.∈S        C.∈S        D.∈S
已知:Fe2O3(s)+3/2C(s)=3/2CO2(g)+2Fe(s)△H=234.1kJ·mol−1C(s...
  • 已知:Fe2O3(s)+3/2C(s)=3/2CO2(g)+2Fe(s)△H=234.1kJ·mol−1C(s...

  • 問題詳情:已知:Fe2O3(s)+3/2C(s)=3/2CO2(g)+2Fe(s)△H=234.1kJ·mol−1C(s)+O2(g)=CO2(g)△H=−393.5kJ·mol−1則2Fe(s)+3/2O2(g )=Fe2O3(s) 的△H是( )A. −824.4kJ·mol−1           B. −627.6kJ·mol−1C. −744.7kJ·mol−1         D. ...
  • 29976
已知反應①:CO(g)+CuO(s)⇌CO2(g)+Cu(s)和反應②:H2(g)+CuO(s)⇌Cu(s)+...
已知:2Fe(s)+O2(g)=2FeO(s)△H=-544kJ·mol-14Al(s)+3O2(g)=2Al...
  • 已知:2Fe(s)+O2(g)=2FeO(s)△H=-544kJ·mol-14Al(s)+3O2(g)=2Al...

  • 問題詳情:已知:2Fe(s)+O2(g)=2FeO(s)△H=-544kJ·mol-14Al(s)+3O2(g)=2Al2O3(s)△H=-3350kJ·mol-1則2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)的△H是(   )A.-859kJ·mol-1                          B.+859kJ·mol-1C.-1403kJ·mol-1                 ...
  • 15825
對反應:CaCO3(s)=CaO(s)+CO2(g) △H(298K)=178.3KJ/mol △S(298K...
  • 對反應:CaCO3(s)=CaO(s)+CO2(g) △H(298K)=178.3KJ/mol △S(298K...

  • 問題詳情:對反應:CaCO3(s)=CaO(s)+CO2(g) △H(298K)=178.3KJ/mol △S(298K)=169.6J/(mol・K)假定反應焓變和熵變都不隨溫度變化,通過計算說明碳*鈣分解的最低溫度。【回答】解:△S(298K)=169.6J/(mol・K)=0.1696KJ/(mol・K)   △G=AH(298K)-T・△S(298K)      =178.3KJ/mol-T×0.1696KJ/(mol・K)<0...
  • 32151