- 问题详情:如图,矩形ABCD的对角线AC,BD相交于点O,点E,F在BD上,BE=DF.(1)求*:AE=CF;(2)若AB=6,∠COD=60°,求矩形ABCD的面积.【回答】:(1)*:∵四边形ABCD是矩形,∴OA=OC,OB=OD,AC=BD,∠ABC=90°.∵BE=DF,∴OE=OF.又∵∠AOE=∠COF,∴△AOE≌△COF,∴AE=CF.(2)∵OA=OC,OB=OD,AC=BD,∴OA=OB.∵∠AOB=∠COD=60°,∴△AOB是...
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- DriverdevelopmentforDF1andCDMA/GPRSintegration;BasedonDF1protocol,thedesignandrealizationoftrafficlightscontrolexperimentwerestudiedusingRockwellcontrollerandRockwellsoftware....
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