一元二次方程x2+x﹣6=0的根的情况是（　　）                               ...

问题详情：

一元二次方程x2+x﹣6=0的根的情况是（　　）                                                    

A．有两个相等的实根       B．没有实数根                                                          

C．有两个不相等的实根    D．无法确定                                                             

【回答】

C【考点】根的判别式．                                                                                     

【分析】由根的判别式△=b2﹣4ac，即可判定一元二次方程x2+x﹣6=0的根的情况．                  

【解答】解：∵△=b2﹣4ac=12﹣4×1×（﹣6）=25＞0，                                             

∴有两个不相等的实根．                                                                                    

故选C．                                                                                                             

知识点：解一元二次方程

题型：选择题